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(2x-1)(3x+2)-(x-2)^2=5x(x-2)+4
We move all terms to the left:
(2x-1)(3x+2)-(x-2)^2-(5x(x-2)+4)=0
We multiply parentheses ..
(+6x^2+4x-3x-2)-(x-2)^2-(5x(x-2)+4)=0
We calculate terms in parentheses: -(5x(x-2)+4), so:We get rid of parentheses
5x(x-2)+4
We multiply parentheses
5x^2-10x+4
Back to the equation:
-(5x^2-10x+4)
6x^2-5x^2+4x-3x-(x-2)^2+10x-2-4=0
We add all the numbers together, and all the variables
x^2+11x-(x-2)^2-6=0
We move all terms containing x to the left, all other terms to the right
x^2+11x-(x-2)^2=6
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